Which quadratic equation defines the function that has zeros at -8 and 6? A) x2 + 2x - 48 = 0 B) x2 - 2x - 48 = 0 C) x2 + 2x + 48 = 0 D) x2 - 2x + 48 = 0

The quadratic equation that defines the function that has -8 and 6 as zeroes is A) which is [tex]X^{2}[/tex] + 2x-48 = 0.what are zeroes of a function?Zeros of a function are values of that function that renders the function equal to zero(0).Analysis:If -8 and 6 are the x roots of a certain quadratic equation,then, x = 6 or x = - 8which means x-6 = 0 or x+8 = 0 are factors of this quadratic equation.(x-6)(x+8) = 0By expanding[tex]X^{2}[/tex]+8x-6x-48 = 0[tex]X^{2}[/tex] + 2x - 48 = 0.In conclusion, the quadratic equation that defines the function that has zeros at -8 and 6 is [tex]X^{2}[/tex] +2x -48 = 0.Learn more about functions : brainly.com/question/2833285#SPJ2