What is the equation of the line through (3,7) that is perpendicular to the line through points (-1,-2) and (5,3)?Please help :')

the line through points (-1,-2) and (5,3)
slope=(3-(-2))/(5-(-1))=5/6
for a perpendicular line slope =-6/5=-1.2
y=(-6/5)x+b
7=(-6/5)*3+b
7=-18/5+b
7=-36/10+b
7=-3.6+b
b=10.6
y=-1.2x+10.6