For a standard normal distribution, find the approximate value of P(-0.78 = z = 1.16). Use the portion of the standard normal table below to help answer the question.(z)0.000.160.220.781.001.161.782.00(Probabilities)0.50000.56360.58710.78230.84130.87700.96250.9772

Correction:I think the question should be like that find the approximate value of P(-0.78 < z < 1.16)?
Now,the symbol Ф represent the cumulative density.first find the Ф(1.16) from the above given table which is equal to 0.8770.Now,find the Ф(-0.78) .in our table we are given the value of Ф(0.78)=0.7823so as the curve is symmetrical Ф(-0.78)=1-0.7823=0.2177
P(-0.78 < z < 1.16) = Ф(1.16)-Ф(-0.78) = 0.8770-0.2177 = 0.6593