Q:

If a couple were planning to have three​ children, the sample space summarizing the gender outcomes would​ be: bbb,​ bbg, bgb,​ bgg, gbb,​ gbg, ggb, ggg.a. construct a similar sample space for the possible health outcomes​ (using h for healthy and s for sick​) of two children.b. assuming that the outcomes listed in part​ (a) were equally​ likely, find the probability of getting two healthy children.c. find the probability of getting exactly one healthy child and one sick child.

Accepted Solution

A:
Answer:a.S={hh,sh,hs,ss}b.tex]\frac{1}{4}[/tex]c.[tex]\frac{1}{2}[/tex]Step-by-step explanation:We are given that a sample space of three childrenS={bbb,bbg,bgb,bgg,gbb,gbg,ggb,ggg}a.We have to construct similar space for two children where h for healthy and s for sick.Then the sample space of two childrenS={hh,sh,hs,ss}b.Number of cases favorable to two healthy children=1Total number of  cases=4Number of cases for two healthy children=1Probability =Number of favorable cases divided  by total number of casesProbability=[tex]\frac{1}{4}[/tex]Hence, the probability of getting two healthy children=[tex]\frac{1}{4}[/tex]c.We have to find the probability of getting exactly one healthy child and one sick childNumber of cases of one healthy child and one sick child={hs,sh}=2Probability=[tex]\frac{2}{4}=\frac{1}{2}[/tex]Hence, the probability of getting exactly one healthy child and one sick child=[tex]\frac{1}{2}[/tex]