Q:

Find the absolute minimum and absolute maximum values of f on the given interval. f(x) = (x2 βˆ’ 1)3, [βˆ’1, 6] absolute minimum correct: your answer is correct. absolute maximum

Accepted Solution

A:
The minimum value being cubed is -1, so (-1)Β³ = -1 is the absolute minimum value of the function.

The absolute maximum on the interval is f(6) = 42875.