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What is the solution of the linear quadratic system or equations? Y=x^2+5x-3Y-x=2
4 months ago
Q:
What is the solution of the linear quadratic system or equations? Y=x^2+5x-3Y-x=2
Accepted Solution
A:
because y=x+2, x^2+5x-3=x+2, therefore x^2+4x-5=0, so (x-1)(x+5), so x=-5,1