The center of a circle is located at (5, −5) . The radius of the circle is 3.What is the equation of the circle in general form? x2+y2+10x−10y+41=0 x2+y2−10x+10y+47=0 x2+y2−10x+10y+41=0 x2+y2+10x−10y+47=0
Accepted Solution
A:
The equation of the circle whose center is located at (5, -5) and the radius is 3 units is in general form is,[tex]x^2+y^2-10x+10y+41=0[/tex]What is the equation of circle?The equation of the circle is the equation which is used to represent the circle in the algebraic equation form with the value of centre point in the coordinate plane and measure of radius.The standard form of the equation of the circle can be given as,[tex](x-h)^2+(y-k)^2=r^2[/tex]Here (h,k) is the center of the circle and (r) is the radius of the circle.The center of a circle is located at (5,−5) . The radius of the circle is 3. Thus,[tex]h=5\\k=-5\\r=3[/tex]Put these values in the above equation as,[tex](x-5)^2+(y-(-5))^2=3^2\\(x-5)^2+(y+5)^2=9\\x^2+25-10x+y^2+25+10y-9=0\\x^2+y^2-10x+10y+41=0[/tex]Thus, the equation of the circle whose center is located at (5, -5) and the radius is 3 units is in general form is,[tex]x^2+y^2-10x+10y+41=0[/tex]Learn more about the equation of circle here;