I WILL GIVE BRAINLIEST FOR Correct Answer A plane is located at C on the diagram. There are two towers located at A and B. The distance between the towers is 7,600 feet, and the angles of elevation are given.EXPLAIN YOUR ANSWER a. Find BC, the distance from Tower 2 to the plane, to the nearest foot. b. Find CD, the height of the plane from the ground, to the nearest foot.
Accepted Solution
A:
Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.
in the triangle ACD sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1
in the triangle BCD sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2 equation 1=equation 2 sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16] BD=15979 ft
in the triangle BCD cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491 BC=17491 ft
the answer part 1) BC is 17491 ft
Part 2) Find CD, the height of the plane from the ground, to the nearest foot.
CD=sin24*BD ( remember equation 2) BD=15979 ft CD=sin24*15979 -----------> CD=6499 ft