Amanda measures the top of an 80 cm desk to be 82.4 cm. Dwayne measures the height of a 140 cm cabinet to be 137.2 cm. Which student has a greater percent error? Explain your reasoning.

Percent error is given by formula [tex] Percent \; Error = \frac{Measured \; value}{correct \; value} \times 100 \% [/tex]Error calculation for Amanda:Accurate measurement value of the top of desk = 80 cmMeasured value by Amanda = 82.4Error = 82.4-82 = 2.4Now plug these values to find the percent error.[tex] Percent \; Error \; of \; Amanda = \frac{2.4}{80} \times 100 \% = 0.03 \times 100 \%= 3 \% [/tex]----Error calculation for Dwayne:Accurate measurement value of the cabinet = 137.2 cmMeasured value by Dwayne = 140Error = 140-137.2= 2.8Now plug these values to find the percent error.[tex] Percent \; Error \; of \; Dwayne= \frac{2.8}{140} \times 100 \% = 0.02 \times 100 \%= 2 \% [/tex]3% is clearly more than 2%.Hence final answer will be:Amanda has greater percent error than Dwayne.