AB lies in the same plane as circle P, which has a radius of 6 mm. At how many points will AB intersect circle P if PA is 7mm and PB is 3mm?

PA is longer than the radius of the circle so Point A must be outside of the circle.

PB is less than the radius of the circle so Point B must be inside the circle.

Since the ray is going from A to B it is coming inside the circle and continuing in the other direction, therefore, it must exit the circle, giving us 2 contact points