Solve for f. d = 16ef² f=±4de‾‾‾√ f=±4de√e f=±de√4e f=±de√16

Answer:The value of f out of given expression [tex]d=16ef^2[/tex] is [tex]\frac{\pm 1}{4}\sqrt{\frac{d}{e}}[/tex]Step-by-step explanation:Given : expression [tex]d=16ef^2[/tex]We have to solve for f.Consider the given expression  [tex]d=16ef^2[/tex]Divide both side by 16e, we get,[tex]\frac{d}{16e}=f^2[/tex]Now, taking square root, both sides, we have,[tex]\sqrt{\frac{d}{16e}}=\sqrt{f^2}[/tex]Simplify, we get,[tex]\sqrt{\frac{d}{16e}}=f[/tex]We know [tex]\sqrt{16}=\pm 4[/tex] , we get,[tex]\frac{\pm 1}{4}\sqrt{\frac{d}{e}}=f[/tex]Thus, The value of f out of given expression [tex]d=16ef^2[/tex] is [tex]\frac{\pm 1}{4}\sqrt{\frac{d}{e}}[/tex]