Which direction does the graph of the equation shown below open? Y^2-4x+4y-4=0A. Left B. Up C. DownD. Right
Accepted Solution
A:
we have that Y²-4x+4y-4=0 you can rewrite the equation as 4x=y²+4y-4 x=(y²/4)+y-1 x=0.25*(y²+4y)-1 x=0.25*(y²+4y+4-4)-1 x=0.25*(y²+4y+4)-5 x=0.25*(y+2)²-5
the equation of the parabola is of the form x=a(y-k)²+h is a horizontal parabola where (h,k)-----> is the vertex-----> (-5,-2) a=0.25 a> 0--------> open to the right