A garden measures 6 feet by 7 feet. A gravel path of constant width is placed around the garden so that the total area is 72 square feet. What is the width of the gravel path? Enter your answer in the box.
Accepted Solution
A:
let x---------> the width of the gravel path
we know that 72=(2x+6)*(2x+7)----> 72=4x²+14x+12x+42-------> 4x²+26x-30=0
using a graph tool-----> to resolve the second order equation see the attached figure
the solution is x=1
the answer is the width of the gravel path is 1 ft