Q:

30 pt, easyishPLEASE HELP AND WRITE SOMETHING GOOD.HELP PLEASEWhat is the starting point and rate of change fora(x) = 210(1.12)xplease help FAST

Accepted Solution

A:
The starting point is (0 , 210) and the rate of change is 1.12Step-by-step explanation:The form of the exponential function is [tex]f(x)=a(b)^{x}[/tex] , wherea ix the initial value ⇒ (at x = 0)b is the factor of growth/decay of the function ⇒ (rate of change)If b > 1, then the function is growthIf 0 < k < 1, the the function is decay∵ The function is [tex]a(x)=210(1.12)^{x}[/tex]∵ At the starting point x = 0- Substitute x in the function by 0∴ [tex]a(0)=210(1.12)^{0}[/tex]- Remember any number to power of zero = 1 except 0∴ [tex](1.12)^{0}=1[/tex]∴ a(0) = 210(1) = 210∵ a(x) = y∴ The starting point is (0 , 210)∵ The from of the exponential equation is [tex]f(x)=a(b)^{x}[/tex]∵ [tex]a(x)=210(1.12)^{x}[/tex]- Compare the two function∴ b = 1.12∵ b is the rate of change of the function∴ The rate of change of the function is 1.12The starting point is (0 , 210) and the rate of change is 1.12Learn more:You can learn more about logarithmic function in brainly.com/question/11921476#LearnwithBrainly