Q:

Write the equation of the line perpendicular to + = that passes through (βˆ’,βˆ’). Write your answer in slope-intercept form.

Accepted Solution

A:
Answer:y = 0.25x - 5Step-by-step explanation:Given line is 4x + y = 3or y = -4x + 3Comparing this with slope-intercept form y = mx + c :slope of this line is -4Product of slopes of perpendicular lines = -1β‡’ slope of a line perpendicular to this is [tex]\frac{-1}{-4}[/tex] = [tex]\frac{1}{4}[/tex] = 0.25This line also passes through the point (-4,-6)The equation of a line having slope m and passing through a point (h,k) is y - k = m(x - h)β‡’ equation of line perpendicular to given line is y - (-6) = 0.25Γ—{x - (-4)}β‡’ y + 6 = 0.25Γ—(x + 4)β‡’ y + 6 = 0.25x + 1β‡’ y = 0.25x - 5This is in the slope-intercept form y = mx + c with slope m = 0.25 and y-intercept (0,-5)