What is the equation of a line that is parallel to −x+3y=6 and passes through the point (3, 5) ? Enter your answer in the box.

Answer:x - 3y = -12Step-by-step explanation:First find the slope by converting the given equation to slope-intercept form.-x + 3y = 63y = x + 6y = 1/3x + 2- meaning that the slope = 1/3.Y - y1 = m(x - x1)  where m = 1/3 and (x1, y1) = (3, 5):-y - 5 = 1/3(x - 3)   Multiply each tern by 3:-3y - 15 = x - 3x - 3y = -12   is the required equation