Apple uses cheap labor in factories in China to manufacture its cell phones. The probability that a phone is defective is 0.02. What is the probability that a sample of 500 iPhones will contain exactly 5 defective phones?a.) What is the average number of defective phones? (No decimals)b.) The probability of getting 5 defective phones? (To thousandths)

Let x be the random variable representing defective phone. Let n be the sample size. Let p be the probability that phone is defective.Given: n=500, p= 0.02 From given information we know that x is random variable such that p is the probability of success and it is constant for each trial. Sample size n is fixed. X follows Binomial distribution with parameters n=500 and p=0.02a). The average number of defective phone E(x) = n*p = 500 * 0.02 = 10The average number of defective phones is 10.b)Probability of getting 5 defective phones.P(X=5) = [tex] (nCx) p^{x} (1-p)^{n-x} [/tex] = [tex] (500C5) 0.02^{5} (1-0.02)^{500-5} [/tex] = 0.037The probability of getting exactly 5 defective is 0.037.