For this case we have the following expression:
[tex]\frac {x-2} {x ^ 2 + 1} + \frac {x + 3} {x ^ 2 + 1}[/tex]We observe that both fractions have the same denominator. Therefore, we add the numerators.
We have then:
[tex]\frac {(x-2) + (x + 3)} {x ^ 2 + 1}[/tex]Then, rewriting the expression we have:
[tex]\frac {2x + 1} {x ^ 2 + 1}[/tex]Answer:
The equivalent expression is given by:
[tex]\frac {2x + 1} {x ^ 2 + 1}[/tex]