WILL GIVE BRAILYEST TO WHOEVER ANSWERS CORRECTLY FIRST: On a coordinate plane, a line is drawn from point C to point D. Point C is at (negative 1, 4) and point D is at (2, 0). Point C has the coordinates (–1, 4) and point D has the coordinates (2, 0). What is the distance between points C and D? d = StartRoot (x 2 minus x 1) squared + (v 2 minus v 1) squared EndRoot units
Accepted Solution
A:
Answer: 5=============================Work Shown:point C = (x1,y1) = (-1,4)point D = (x2,y2) = (2,0)Distance Formula[tex]d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}[/tex][tex]d = \sqrt{(2-(-1))^2+(0-4)^2}[/tex][tex]d = \sqrt{(2+1)^2+(0-4)^2}[/tex][tex]d = \sqrt{(3)^2+(-4)^2}[/tex][tex]d = \sqrt{9+16}[/tex][tex]d = \sqrt{25}[/tex][tex]d = 5[/tex]The distance between point C and point D is 5 unitsThis is equivalent to saying that segment CD is 5 units long.