A triangle has sides of length 11 m, 12 m, and 16 m.What is the measure of the angle opposite the side that is 16 m long? Round to the nearest degree.
Accepted Solution
A:
we know that the law of cosines formulas established c²=a²+b²-2*a*b*cos C-----> cos C=[a²+b²-c²]/[2*a*b] a=11 m b=12 m c=16 m so cos C=[11²+12²-16²]/[2*11*12]---> cos C=0.0341 C=arc cos (0.0341)-------> C=88.05°