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Write the general term of the following geometric progressions: a) 4,12,36,108,....
5 months ago
Q:
Write the general term of the following geometric progressions: a) 4,12,36,108,....
Accepted Solution
A:
General term of gp $$Tn = ar^n^-^1$$ given a1 = 4, a2 = 12 $$r = \frac{a2}{a1} = \frac{12}{4} = 3$$ therefore, $$Tn = 4(3)^n^-^1$$