Q:

what is the coefficient of the x^6y^3 term in the expansion of (x+2y)^9?

Accepted Solution

A:
use the binomial expansion formula for (a+b)^n 
(sorry, cannot type it here, please google)
n!/[(n-k)!k!]a^(n-k)b^k
x^6y^3 is when k=3
in this case, n=9
so the coefficient when k=3 is: 9!/[(9-3)!3!]*(2)^3= [tex] \frac{9*8*7}{3*2*1} *2^3=672[/tex]