Q:

Write an equation of the line passing through point P(βˆ’8, 0) that is perpendicular to the line 3xβˆ’5y = 6

Accepted Solution

A:
Answer:y = -5/3 * x - 40/3Step-by-step explanation:A perpendicular line has an opposite and a reciprocal of the slope.Your equation should be:-5y = -3x +6Divide all parts by -5.y = 3/5x - 6/5Since the perpendicular line has an opposite and a reciprocal of the slope, the slope will be -5/3.Now you must make an equation in point-slope form. This is an example of that form. You will need at least one point to make this equation work. In this case we have (-8,0).In put the y and x coordinates like this:y - 0 = -5/3(x - (-8)Start solving the equation.y - 0 = -5/3(x + 8)y - 0 = -5/3 * x - 40/3y = -5/3 * x - 40/3This is your equation.y = -5/3 * x - 40/3(You can make it -5/3x in your answer but it looks weird online. You may think that it is -5 divided by 3 times x, but it actually is 5/3 times x. That's why I wrote it as y = -5/3 * x - 40/3)