What exponential function is the best fit for the data in the table?x f(x)2 −33 04 12 f(x) = 4(4)x − 1 + 4 f(x) = 4(4)x − 1 − 4 f(x) = one fourth(4)x − 1 + 4 f(x) = one fourth(4)x − 1 − 4
Accepted Solution
A:
Answer: fourth option
[tex] \frac{1}{4} 4^{x-1}-4[/tex]
Explanation:
1) the pair x = 3 f(x) = 0, leads you to probe this:
f(3) = 0 = A [4 ^ (3 - 1) ] + C = 0
=> A [4^2] = - C
A[16] = - C
if A = 1/4
16 / 4 = 4 => C = - 4
That leads you to the function f(x) = [1/4] 4 ^( x - 1) - 4
2) Now you verify the images for that function for all the x-values of the table: