The width of a rectangle is 6 2/3 inches. The length of the is twice it’s width. What so the perimeter of the rectangle?

[tex]\text {Width = } 6\dfrac{2}{3} \text { inches} [/tex]


The length is twice its width:
[tex]\text {Length = } 2 \times 6\dfrac{2}{3} \text { inches}[/tex]

Change to improper fraction:
[tex]\text {Length = }2 \times \dfrac{20}{3} \text { inches}[/tex]

Combine into single fraction:
[tex]\text {Length = } \dfrac{40}{3} \text { inches}[/tex]


Find Perimeter :
[tex]\text {Perimeter = Length + Length + Width + Width} [/tex]

[tex]\text {Perimeter = } \dfrac{40}{3} + \dfrac{40}{3} + \dfrac{20}{3} + \dfrac{20}{3} = \dfrac{120}{3} = 40 \text { inches}[/tex]


[tex]\bf \text {Answer: Perimeter = 40 inches}[/tex]