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What are the zeros of the quadratic function f(x) = 8x2 – 16x – 15? x = –1 – and x = –1 + x = –1...
4 months ago
Q:
What are the zeros of the quadratic function f(x) = 8x2 – 16x – 15? x = –1 – and x = –1 + x = –1 – and x = –1 + x = 1 – and x = 1 + x = 1 – and x = 1 +
Accepted Solution
A:
8x^2 - 16x - 15 = 0 x = [ -(-16) +/- sqrt((-16)^2 - 4*8*-15) / ] 2*8= 2.696, -0.696