What are the sine, cosine, and tangent of 11 pi over 6 radians? sin θ = square root 3 over 2; cos θ = 1 over 2; tan θ = square root 3 over 3 sin θ = negative square root 3 over 2; cos θ = 1 over 2; tan θ = negative square root 3 over 3 sin θ = negative 1 over 2; cos θ = square root 3 over 2; tan θ = negative square root 3 over 3 sin θ = 1 over 2; cos θ = negative square root 3 over 2; tan θ = negative square root 3 over 3
Accepted Solution
A:
we know that
θ=11 pi /6 radians-----> 11*180/6----> 330° 330°----> belong to the IV quadrant so cos θ----> is positive sin θ----> is negative tan θ----> is negative
330°-----> 360°-330°---> 30°
sin 30°------> 1/2 sin θ=-1/2-----> remember that sin θ is negative
cos 30°------> √3/2 cos θ=√3/2
tan 30°------> (1/2)/(√3/2)----> √3/3 tan θ=-√3/3-------> remember that tan θ is negative
the answer is sin θ = negative 1 over 2; cos θ = square root 3 over 2; tan θ = negative square root 3 over 3