The floor of a conference hall can be covered completly with tiles.Its length is 36ft. longer than its width.The area of the floor is less than 2040square ft.How would you represent the with of the floor?How about its lenght?What mathematical sentence would represent the given situation?What are the possible dimensions of the floor?How about the possible areas of the floor?Would it be realistic for the floor to have an area of 144sq.ft?Explain your answer.

Answer:Step-by-step explanation:Given Area of a floor = 2040ft²If Its length is 36ft. longer than its width, then L = W+36Area = LWL is the lengthW is the widthA <  W(W+36)2040 < W²+36W0<W²+36W-2040 W²+36W-2040 >0W = -36±√36²-4(-2040)/2W =  -36±√1296+8160)/2W =  -36±√9456/2W =  -36±97.25/2W = -36+97.25/2W = 61.24/2W > 30.62ftSince L = W+36L > 30.62+36L > 66.62ftThe width of the floor is 30.62ftThe length is 66.62ftThe mathematical sentence would represent the given situation is the width is greater than 30.62ft while the length must be greater than 66.62ftThe possible dimension of the floor is 31ft by 67 ftThe possible areas is 31*67 = 2077ft²It won't be realistic to get an area of 144sqft because the initial area is greater than 144. Hence the feasible area will be greater than 2040ft²