14. You start an investment account with $3000 and save $100 each month. Write arule to represent the total amount of money you invest into your account as anarithmetic sequence. How much money will you have invested after 12 months?
Accepted Solution
A:
Answer:4200Step-by-step explanation:In an arithmetic sequence equation t=a + (n-1)d, a is the starting value. In this case, a=3000. Although, since the initial investment is not considered the first month, the equation is t = a + dn.d is the rate of change. In this case, the rate of change is 100 for every month, n.Substitute these values from the problem to get an equation:t = 3000 + 100nt means the total amount of money we have for the amount of months (n) that passed.Sub n for 12.t = 3000 + 100nt = 3000 + 100(12)t = 4200You will have $4200 after 12 months of investment.