The hypotenuse of a right triangle is twice the length of one of the legs. the length of the other leg is 192‾‾‾‾√ feet. find the lengths of the leg and hypotenuse.
Accepted Solution
A:
The solution is:
The following are the given:
h = 2a
b = √192
a^2 + b^2 = h^2
substituting…
a^2 + 192 = (2a)^2
a^2 + 192 = 4a^2
3a^2 = 192
a^2 = 64
= √64
a = 8
so h = 2*8
The answers are:
= 16 ft would be the hypotenuse.= 8 is the length of the legs.