The asymptote of the function f(x) = 3x + 1 – 2 is_________ . Its y-intercept is_____ . Options for the first blank is y= -2y= -1y= 1y= 2Options for the second is(0,-2)(0,-3)(0,1)(0,-1)

Answer:In first blank : y = - 2,In second blank : ( 0, 1 )Step-by-step explanation:Given function is,[tex]f(x)=3^{x+1}-2[/tex]The horizontal asymptote of the function f(x),[tex]y=lim_{x\rightarrow \infty} f(x)[/tex][tex]y=lim_{x\rightarrow \infty} 3^{x+1}-2[/tex][tex]y=3^{\infty+1}-2[/tex][tex]y=3^\infty - 2[/tex][tex]y=0-2[/tex]⇒ y = -2First option is correct.Also, the function has no vertical asymptote,2. For finding the y-intercept, x = 0,[tex]f(0)=3^{0+1}-2=3-2=1[/tex]Hence, the y-intercept = (0,1)Third option is correct.