the area of a triangular block is 64 sq in. if the base os the triangle is twice the height, how long are the base and the height of the triangle
Accepted Solution
A:
------------------------------------------------------ Define x : ------------------------------------------------------ Let the height be x. Height = x Length = 2x
------------------------------------------------------ Solve for x: ------------------------------------------------------ Area of triangle = 1/2 x base x height 64 = 1/2 (x)(2x) x² = 64 x = √64 x = 8
------------------------------------------------------ Find the height and the length: ------------------------------------------------------ Height = x = 8 in Length = 2x = 2(8) = 16 in
--------------------------------------------------------------------------- Answer: The base is 16 in and the height is 8 in. ---------------------------------------------------------------------------