Show at least the first step of your work as you solve this system by elimination. Provide your final answer as an ordered pair. 4x + 28y = -52 -4x - 14y = 28

the first step to solve this is to write your equation as a system of equations
[tex] \left \{ {{4x + 28y = 28} \atop {-52 - 4x - 14y = 28}} \right. [/tex]
now divide both sides of the top equation by 2
[tex] \left \{ {{2x + 14y = 14} \atop {-52 - 4x - 14y = 28}} \right. [/tex]
now simplify the bottom expression
[tex] \left \{ {{2x + 14y = 14} \atop {-4x - 14y = 80}} \right. [/tex]
now,, sum the equations vertically to eliminate at least one variable
-2x = 94
then divide both sides of the equation by -2
x = -47
substitute the given value of x into the simplest equation of 4x + 28y = 28
4x (-47) + 28y = 28
next youll need to solve the equation for y
y = 54/7
the possible solution of the system is the order pair (x,y),, so add that into your equation
(x,y) = ( -47, 54/7 )
check if the given ordered pair is the solution of the system of equations by doing the following:
4 x (-47) + 28 x 54/7 = -52 - 4 x (-47) - 14 x 54/7 = 28
now simplify the above expression
28 = 28 = 28
since all of the inequalities are true,, the ordered pair is the solution of your system
(x,y) = ( -47, [tex] \frac{54}{7} [/tex] )
this means that the correct answer to your question is (x,y) = ( -47, [tex] \frac{54}{7} [/tex] )
let me know if you have any further questions
:)