Sergey is solving 5x2 + 20x – 7 = 0. Which steps could he use to solve the quadratic equation by completing the square? Check all that apply. 5(x2 + 4x + 4) = –7 + 20 x + 2 = 5(x2 + 4x) = 7 5(x2 + 4x + 4) = 7 + 20 5(x2 + 4x) = –7 x + 2 =

Answer:[tex]5(x^2+4x)=7[/tex]Option 2 and 3 is correct.Step-by-step explanation:Case (I). Given equation is[tex]5x^2+20x-7=0[/tex]Firstly, we will add of 7 in both sides[tex]5x^2+20x-7+7=7[/tex]Now, same variable of opposite sign is cancelled[tex]5x^2+20x=7[/tex]Now, taking 5 common from left side[tex]5(x^2+4x)=7[/tex]Case (II).Given equation[tex]5x^2+20x-7=0[/tex]Firstly, we will add of 7 in both sides[tex]5x^2+20x=7[/tex]Now, we will add of 20 in both sides[tex]5x^2+20x+20=7+20[/tex]Now, taking common of 5 from left side[tex]5(x^2+4x+4)=7+20[/tex]So, The next step on solving completing square is [tex]5(x^2+4x)=7[/tex] and [tex]5(x^2+4x+4)=7+20[/tex]