In the diagram, AB is divided into equal parts. The coordinates of point A are _____, and the coordinates of point I are______ .
Accepted Solution
A:
Answer:The coordinates of point A are (-10,-4). The coordinates of I are (-3.875,-10.125).Step-by-step explanation:It is given that the the line AB is divided into equal parts. Therefor distance between two consecutive points are equal.The point D is mid point of A and F.[tex](x,y)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex][tex](-8.25,-5.75)=(\frac{x+(-6.5)}{2},\frac{y+(-7.5)}{2})[/tex][tex]-8.25=\frac{x-6.5}{2}[/tex][tex]-16.50=x-6.5[/tex][tex]-10=x[/tex][tex]-5.75=\frac{y-7.5}{2}[/tex][tex]-11.50=y-7.5[/tex][tex]-4=y[/tex]Therefore the coordinates of A are (-10,-4).Similarly the pint H is midpoint of F and B.[tex](-4.75,-9.25)=(\frac{x+(-6.5)}{2},\frac{y+(-7.5)}{2})[/tex]The values of x and y are,[tex]x=-3[/tex][tex]y=-11[/tex]Therefore the coordinates of B are (-3,-11).The point I is mid point of HB. H(-4.75,-9.25) and B(-3,-11).[tex](x,y)=(\frac{-4.75-3}{2},\frac{-9.25-11}{2})[/tex][tex](x,y)=(-3.875,-10.125)[/tex]Therefore the coordinates of I are (-3.875,-10.125).