Find the coefficient of the fourth term of (x+2)^5 •32 •48 •64 •80 Find the coefficient of the third term of (3x-1)^5 •248 •270 •360 •505Find the coefficient of the third term of (a+5b^2)^4 •150•500 •625•1500
Accepted Solution
A:
The coefficients of the binomial expansion [tex](a+b)^n[/tex], where n is the row number, is given in the Pascal's triangle shown below.
First, to find the coefficient of the fourth term of (x+2)^5 we look at row 5, term 4. The coefficient there is 10.
But, we must also remember that the term 2 also is taken to a certain power here. Mainly , for each term, the power of 2 is as follows:
2^0, 2^1, 2^2, 2^3=8.
So, in total we have: 10*8=80.
Second, to find the coefficient of the third term of (3x-1)^5 we again go to the row 5, this time term 3 and we have 10 there. Now we must check how each of (3x) and 1 expand, now being careful about the sign as well.
we have: (3x)^5 (1) -(3x)^4 (1) (3x)^3(1)=27x^3.
Thus, the coefficient of the third term is 27*10=270.
Third, we want to find the coefficient of the third term of (a+5b^2)^4. We look at row 4, term 3. There we have 6.