Start with the second equation. So start with -15x-3y = 3
Think of -3y as -3( y ). The parenthesis doesn't matter at this point, but will be useful for the next step.
So we have -15x - 3( y ) = 3. We can replace the y with 5x-1 since y = 5x-1 is the first equation
Doing so has us go from this -15x - 3( y ) = 3 to this -15x - 3(5x - 1) = 3
After this point, we solve for x like normal -15x - 3(5x-1) = 3 -15x - 15x+3 = 3 -30x + 3 = 3 -30x + 3 - 3 = 3-3 ... subtract 3 from both sides -30x = 0 -30x/(-30) = 0/(-30) .... divide both sides by -30 x = 0
So if x = 0 then y is... y = 5*x-1 y = 5*0-1 y = 0-1 y = -1
There is only one solution and it is (x,y) = (0,-1)
Answer: Choice A
Side Note: this is where the two graphs cross or intersect