The velocity-time graph for a two-stage rocket is shown below. Use the graph and your understanding and of slope calculations to determine the acceleration of the rocket during the following time interval.

Answer:a=[tex]40 ms^{-2} for 0\leq t\leq 1[/tex][tex]20ms^{-2} for 1\leq t\leq 4[/tex][tex]-20ms^{-2} for 4\leq t\leq \infty[/tex]Step-by-step explanation:We will find the acceleration in 3 intervals of time(t) and those intervals are:[tex]0\leq t\leq 1[/tex][tex]1\leq t\leq 4[/tex][tex]4\leq t\leq\infty[/tex]We know that acceleration(a) is given by [tex]a= \lim_{\Delta t \to 0} \frac{\Delta v}{\Delta t}[/tex]=Slope of velocity-time graphIn interval [tex]0\leq t\leq 1[/tex],[tex]a=Slope= \frac{\Delta v}{\Delta t}=\frac{40-0}{1-0} =40ms^{-2}[/tex]In interval [tex]1\leq t\leq 4[/tex],[tex]a=Slope= \frac{\Delta v}{\Delta t}=\frac{100-40}{4-1} =20ms^{-2}[/tex]In interval [tex]4\leq t\leq\infty[/tex],[tex]a=Slope= \frac{\Delta v}{\Delta t}=\frac{60-100}{6-4} =-20ms^{-2}[/tex]