Answer:Part A) [tex]sin(A)=\frac{2\sqrt{42}}{23}[/tex]Part B) [tex]cos(A)=\frac{19}{23}[/tex]Part C) [tex]tan(A)=\frac{2\sqrt{42}}{19}[/tex]Step-by-step explanation:Part A) we know thatIn the right triangle ABC of the figure the sine of angle A is equal to divide the opposite side angle A by the hypotenuseso[tex]sin(A)=\frac{BC}{AB}[/tex]substitute the values[tex]sin(A)=\frac{2\sqrt{42}}{23}[/tex]Part B) we know thatIn the right triangle ABC of the figure the cosine of angle A is equal to divide the adjacent side angle A by the hypotenuse so[tex]cos(A)=\frac{AC}{AB}[/tex]substitute the values[tex]cos(A)=\frac{19}{23}[/tex]Part C) we know thatIn the right triangle ABC of the figure the tangent of angle A is equal to divide the opposite side angle A by the adjacent side angle Aso[tex]tan(A)=\frac{BC}{AC}[/tex]substitute the values[tex]tan(A)=\frac{2\sqrt{42}}{19}[/tex]