Suppose you are flying a kite that is 50 feet long. While flying, there is a constant gust of wind that blows the kite to an angle of 60° with the ground. How high, in feet, is the kite above the ground
Accepted Solution
A:
The kite forms a right angled triangle with hypotenuse of 50 ft. The height of the kite above the ground is the opposite of 60° angle.
Using the sine rule, Sin 60 = Height of the kite above the ground/Hypotenuse
Therefore, Height of the kite above the ground = Hypotenuse*Sin 60 = 50 *Sin 60 = 43.3 ft