Determine the general form of the equation for the circle (x – 1)2 + (y + 2)2 = 3.x2 + y2 – 2x + 4y + 2 = 0x2 + y2 – 2x + 4y – 4 = 0x2 + y2 – x + y + 3 = 0x2 + y2 – x + y + 2 = 0

Answer:Step-by-step explanation:(x-1)² + (y+2)² = 3-----------------------------(x-1)²(x-1)(x-1)x² - x - x + 1x² - 2x + 1-------------------------------------(y+2)²(y+2)(y+2)y²+ 2y + 2y + 4y² + 4y + 4---------------------------------------(x² - 2x + 1) + (y² + 4y + 4) = 3x² - 2x + 1 + y² + 4y + 4 = 3x² + y² - 2x + 4y + 1 + 4 = 3x² + y² - 2x + 4y + 5 = 3x² + y² - 2x + 4y + 5 - 3 = 0x² + y² - 2 x + 4y + 2 = 0Mark me brainliest