A rectangular box is to have a square base and a volume of 20 ft3. if the material for the base costs $0.28 per square foot, the material for the sides costs $0.10 per square foot, and the material for the top costs $0.22 per square foot, determine the dimensions of the box that can be constructed at minimum cost.
Accepted Solution
A:
Then the area of the top and bottom are each x^2. Then the height of the box is 40/x^2. Then each side of the box is 40/x square feet. Then the area of all four sides is 160/x square feet. Then the total cost is represented by: 0.30x^2 + 0.05 (160/x) + 0.20x^2 Expand the middle term and combine x^2 terms: 0.50x^2 + 8/x Rewrite for easy differentiation: 0.50x^2 + 8x^-1 Take the derivative: x - 8x^-2 Set the derivative to zero: x - (8/x^2) = 0 Multiply by x^2 x^3 - 8 = 0 Add 8: x^3 = 8 Take the cube root: x = 2 feet So the height is 40/4 = 10 feet So the dimensions with minimum cost are: 2 x 2 x 10 feet.