A field is shaped like the figure shown. What is the area of the field? Use 3.14 for pi

I attached the image for this question.

Answer:
area of field = 146.24 m²

Explanation:
Noticing the figure, we can see that it is composed of three regular shapes:
1- a square
2- a triangle
3- quarter of a circle

We will get the area of each shape separately and then add them to get the total area of the field.

1- getting the area of the square:
area of the square = (side)²
we have the side = 8 m
Therefore:
area of square = (8)² = 64 m² ...............> I

2- getting the area of the triangle:
area of triangle = [tex] \frac{1}{2} [/tex] * base * height
We have the base = 8 m and the height = 8 m
Therefore:
area of triangle = [tex] \frac{1}{2} [/tex] * 8 * 8 = 32 m² ..........> II

3- getting the area of the quarter circle:
area of circle = πr²
area of quarter circle = [tex] \frac{1}{4} [/tex] * πr²
We have π = 3.14 and r = 8 m
Therefore:
area of quarter circle = [tex] \frac{1}{4} [/tex] * 3.14 * (8)² = 50.24 m² .....> III

4- getting the total area of field:
Total area of field = I + II + III
Total area of field = 64 + 32 + 50.24
Total area of field = 146.24 m²

Hope this helps :)