Q:

the members of the boosters organization at your high school bought new balls for the school. They spent $24.00 per basketball and $33.00 per football, spending a total of $882.00. They bought 6 more footballs than basketballs. How many of each type of ball did they buy?

Accepted Solution

A:

6x$33=$198 (difference of 6 footballs)
$882-$198=$684 
$24+$33=$57 (sum of 1 set)
$684÷$57=12(no. of sets)
12x1=12 (basketballs)
12+6=18 (footballs)

Ans:
12 basketballs 
18 footballs