The first step to solve this expression is to use a² - 2a b + b² = (a - b)² to factor the expression [tex] \frac{(x - 2)^{2} }{2 x^{2} + 4x - 16} [/tex] Factor out 2 from the expression [tex] \frac{(x - 2)^{2} }{2( x^{2} + 2x - 8)} [/tex] Write 2x as a difference [tex] \frac{(x-2)^{2} }{2 (x^{2} + 4x - 2x - 8)} [/tex] Factor out x from the expression [tex] \frac{(x - 2)^{2} }{2(x X (x + 4) -2x - 8)} [/tex] Factor out -2 from the expression [tex] \frac{(x-2)^{2} }{2(xX(x+4)-2(x+4))} [/tex] Factor out x + 4 from the expression [tex] \frac{(x-2)^{2} }{2(x+4)X(x-2)} [/tex] Reduce the fraction with x - 2 [tex] \frac{x-2}{2(x+4)} [/tex] Finally,, distribute 2 through the parenthesis to find your answer [tex] \frac{x-2}{2x+8} [/tex] This means that the correct answer to your question is [tex] \frac{x-2}{2x+8} [/tex] . Let me know if you have any further questions :)