kmTwo buses leave a station at the same time and travel in opposite directions. One bus travels 10 - - slower than the other. If the two buses are 1442kilometers apart after 7 hours, what is the rate of each bus?Rate of the slower bus:X5?Rate of the faster bus:
Accepted Solution
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Answer:The speed of faster bus is 108 kmph and The speed of slower bus is 98 kmph .Step-by-step explanation:Given as :The two buses apart 1442 kmThe time taken for apart = 7 hoursLet The speed of faster bus = x kmphThe speed of slower bus = ( x - 10 ) kmphNow Speed = [tex]\dfrac{\textrm distance}{\textrm time}[/tex]∵ Both the buses traveling in opposite direction So, The speed of faster bus + the speed of slower bus = [tex]\dfrac{\textrm distance cover}{\textrm time}[/tex]Or, x + x - 10 = [tex]\frac{1442}{7}[/tex]or, 2 x = 206 + 10or, 2 x = 216∴ x = [tex]\frac{216}{2}[/tex]I.e x = 108 kmphSo, The speed of faster bus = x = 108 kmphAnd The speed of slower bus = ( x - 10 ) = 108 - 10 = 98 kmphHence The speed of faster bus is 108 kmph and The speed of slower bus is 98 kmph . Answer