Q:

I need to make a matrix in reduced row echelon form A real estate agency offers three apartments for rent in New Mexico City. The expected total revenue per month from monthly rentals for the three apartments is $1,600. The individual owners of these apartments bear the monthly maintenance costs of 20% of the rent for the first two apartments and 25% of the rent for the third apartment, which is a total amount of $345. The agency charges a monthly fee equal to 10% of the rent for apartments 1 and 3 and a fee equal to 20% of the rent for apartment 2. The monthly rent plus agency fees totals $1,820. Let x, y, and z represent the monthly rental for the first, second, and third apartments, respectively.

Accepted Solution

A:
Let the three apartments be A, B & CThe rent of A is $xThe rent of B is $yThe rent of C is $zSo x + y + z = 1600     .......(1)Now Maintenance of A is 20% of x = 0.20xMaintenance of B is 20% of y = 0.20yMaintenance of C is 25% of z = 0.25z0.20x + 0.20y + 0.25z = 345 Multiplying by 100 we get20x + 20y + 25 z = 34500Dividing by 5 we get4x + 4y + 5z = 6900              .......(2)Monthly fee of A is 10% of x = 0.10xMonthly fee of B is 20% of y = 0.20 yMonthly Fee of C is 10% of z = 0.10zNow0.10x + 0.20y + 0.10 z= 1820 - 16000.10x + 0.20y + 0.10z = 220Multiplying by 100 we get10x + 20y + 10z = 22000Dividing by 10x + 2y + z = 2200     ....(3)Making a Matrix of equation (1), (2) & (3)[tex] \left[\begin{array}{ccc}1&1&1\\4&4&5\\1&2&1\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right]  =\left[\begin{array}{c}1600\\6900\\2200\end{array}\right]   [/tex]is the required matrix