Answer:[tex]y' = (6,4)[/tex]Step-by-step explanation:Given[tex]y = (3,2)[/tex][tex]x = (4,0)[/tex][tex]z = (2,-2)[/tex][tex]D_{(O,2)}[/tex]RequiredThe image of y[tex]D_{(O,2)}[/tex] implies that y is dilated by a scale factor of 2 across the origin.So, the image of y is:[tex]y' = 2 * y[/tex][tex]y' = 2 * (3,2)[/tex][tex]y' = (6,4)[/tex]