Assuming that a sample (n = 504) has a sample standard deviation of 2.26, what is the upper bound of a 95% confidence interval if the sample mean is 2.96?

The upper bound would be 3.16.

We find the standard error by dividing the standard deviation by the square root of the sample size:

[tex]\frac{\sigma}{\sqrt{n}}=\frac{2.26}{\sqrt{504}}=\frac{2.26}{22.45}=0.10[/tex]

To calculate the margin of error, we multiply the standard error by 2:
0.1(2) = 0.2

For the upper bound, we add this to the mean:
2.96+0.2 = 3.16