Answer:Option B (1,10)Step-by-step explanation:we have[tex]f(x)=2(5^x)[/tex]we know thatIf a ordered pair is on the graph of f(x) then the ordered pair must satisfy the function f(x)Verify each casecase A) (0,0)For x=0[tex]f(x)=2(5^0)\\f(x)=2(1)=2[/tex]Compare the value of f(x) with the y-coordinate of the ordered pair[tex]2\neq 0[/tex]thereforeThe ordered pair is not on the graph of f(x)case B) (1,10)For x=1[tex]f(x)=2(5^1)\\f(x)=2(5)=10[/tex] Compare the value of f(x) with the y-coordinate of the ordered pair [tex]10=10[/tex]thereforeThe ordered pair is on the graph of f(x)case C) (0,10)For x=0[tex]f(x)=2(5^0)\\f(x)=2(1)=2[/tex]Compare the value of f(x) with the y-coordinate of the ordered pair[tex]2\neq 10[/tex]thereforeThe ordered pair is not on the graph of f(x)case D) (10,1)For x=10[tex]f(x)=2(5^{10})\\f(x)=2(9,765,625)=19,531,250[/tex]Compare the value of f(x) with the y-coordinate of the ordered pair[tex]19,531,250\neq 1[/tex]thereforeThe ordered pair is not on the graph of f(x)